Thursday, December 30, 2010

Construct X^2 using compass and straight edge

Question From Vijayan Sir
Given a right triangle with 'unit length' base and 'x unit' height. construct X^2 using compass and straight edge?
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Answer Given by KANI

kani December 29, 2010 10:00 PM

Let ABC be right traingle with Angle A=90,AB=1&AC=x
1. Elongate BA
2. Draw perpendicular bisector of BC to intersect elongated line at O.
3. Find a point D on the same elongated line such that OD=OB

Then AD= x^2
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If x=2, x^2=4
See the picture.


If x=3, x^2=9
See the picture.
To be added:
This question can be interpreted in anotherway using co-ordinate geometry.

See fig.
Elongate CA and consider these perpendiculars BD and CA as X,Y axes respectively.
Take B as 1 and C as x.
Then D is x^2.
Here D can be obtained directly as the point of intersection of X axis and the perpendiculr to BC through C.


2 comments:

കാഡ് ഉപയോക്താവ് said...

Comments problem? Is it publishing properly? Testing

navarang said...

THANKS THANK YOU VERY MUCH